(1/8)^(2-2n)=16

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Solution for (1/8)^(2-2n)=16 equation: 



(1/8)^(2-2n)=16

We move all terms to the left:

(1/8)^(2-2n)-(16)=0



Domain of the equation: 8)^(2-2n)!=0

n∈R



We add all the numbers together, and all the variables

(+1/8)^(-2n+2)-16=0

We multiply all the terms by the denominator


(+1-16*8)^(-2n+2)=0

We add all the numbers together, and all the variables

(-127)^(-2n+2)=0

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